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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+Ksp=2.2*10^-8;//Solubility product of PbSO4//
+Pb=0.01;//concentration of Pb in Pb(NO3)2//
+SO4=Ksp/Pb;//Concentration of SO4 in PbSO4 solution//
+printf('Let us first calculate the maximum concentration of SO4 that can remain in equilibrium with PbSO4 if the concentration of Pb is 0.01M');
+printf('\nConcentration of SO4 in PbSO4 solution=Ksp=2.2*10^-6M\nThe concentration of SO4 should be greater than 2.2*10^-4M in order to precipitate Pb from a 0.01M solution as PbSO4');
+Pb2=Ksp/0.001;
+printf('\nConcentration of Pb in PbSO4 solution=Pb2=2.2*10^-5mol per litre');
+printf('\nHence out of 0.01moles of Pb in a litre only 2.2*10^-5mol per litre remain in solution.the precipitation is almost 99.78percent complete.');
+printf('\nTherefore it can be said that Pb is quantitatively precipitated in these conditions.');