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| author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
|---|---|---|
| committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
| commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
| tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /806/CH8 | |
| parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
| download | Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.gz Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.tar.bz2 Scilab-TBC-Uploads-7f60ea012dd2524dae921a2a35adbf7ef21f2bb6.zip | |
initial commit / add all books
Diffstat (limited to '806/CH8')
| -rw-r--r-- | 806/CH8/EX8.2/82.sce | 15 | ||||
| -rw-r--r-- | 806/CH8/EX8.2/82.txt | 31 | ||||
| -rw-r--r-- | 806/CH8/EX8.3/83.sce | 13 | ||||
| -rw-r--r-- | 806/CH8/EX8.3/83.txt | 22 |
4 files changed, 81 insertions, 0 deletions
diff --git a/806/CH8/EX8.2/82.sce b/806/CH8/EX8.2/82.sce new file mode 100644 index 000000000..9b4886aa5 --- /dev/null +++ b/806/CH8/EX8.2/82.sce @@ -0,0 +1,15 @@ +clc
+pathname=get_absolute_file_path('82.sce')
+filename=pathname+filesep()+'82.sci'
+exec(filename)
+diary('C:\users\Bhavesh\desktop\scilab\82.txt')
+disp("A submarine moves through water at 30 ft/s.At a point A on the submarine 5 ft above the nose,the velocity of the submarine relative to the water is 50 ft/s.Determine the dynamic-pressure difference between this point and the nose,and determine the difference in total pressure between the two points.")
+disp("If the submarine is sationary and the water is movinf past it,The velocity at the nose is zero and the velocity at A is 50ft/s.By selecting the dynamic pressure at infinity as zero")
+E=q^2/2+g*hn
+p1=p*E//Pressure at nose
+p2=p*(E-q1^2/2)//Pressure at point A
+P1=p2-p1//Pressure difference at point A and nose
+P2=p*(g*hn-g*ha+(qn^2-q1^2)/2)
+disp("lb/ft^2",P1,"Hence dynamic pressure difference between point A and nose is=")
+disp("lb/ft^2",P2,"Hence total pressure difference between point A and nose is=")
+diary(0)
diff --git a/806/CH8/EX8.2/82.txt b/806/CH8/EX8.2/82.txt new file mode 100644 index 000000000..e4947d3bd --- /dev/null +++ b/806/CH8/EX8.2/82.txt @@ -0,0 +1,31 @@ +
+ A submarine moves through water at 30 f
+ t/s.At a point A on the submarine
+ 5 ft above the nose,the velocity o
+ f the submarine relative to the wa
+ ter is 50 ft/s.Determine the dynam
+ ic-pressure difference between thi
+ s point and the nose,and determine
+ the difference in total pressure
+ between the two points.
+
+ If the submarine is sationary and the w
+ ater is movinf past it,The velocit
+ y at the nose is zero and the velo
+ city at A is 50ft/s.By selecting t
+ he dynamic pressure at infinity as
+ zero
+
+ Hence dynamic pressure difference betwe
+ en point A and nose is=
+
+ - 2418.75
+
+ lb/ft^2
+
+ Hence total pressure difference between
+ point A and nose is=
+
+ - 2730.0334
+
+ lb/ft^2
diff --git a/806/CH8/EX8.3/83.sce b/806/CH8/EX8.3/83.sce new file mode 100644 index 000000000..90666a4f9 --- /dev/null +++ b/806/CH8/EX8.3/83.sce @@ -0,0 +1,13 @@ +clc
+pathname=get_absolute_file_path('83.sce')
+filename=pathname+filesep()+'83.sci'
+exec(filename)
+diary('C:\users\Bhavesh\desktop\scilab\83.txt')
+disp("A source with strength 0.2m^3/s and a vortex with strength 1 m^2/s are located at the origin.Determine the equations for velocity potential and stream function.What are the velocity components at x=1 m,y=0.5 m?")
+disp("Solution:")
+r=sqrt(x^2+y^2)
+Vr=1/(10*%pi*r)
+Vt=1/(2*%pi*r)
+disp("m/s",Vr,"Vr=")
+disp("m/s",Vt,"Vt=")
+diary(0)
diff --git a/806/CH8/EX8.3/83.txt b/806/CH8/EX8.3/83.txt new file mode 100644 index 000000000..44a79db57 --- /dev/null +++ b/806/CH8/EX8.3/83.txt @@ -0,0 +1,22 @@ +
+ A source with strength 0.2m^3/s and a v
+ ortex with strength 1 m^2/s are lo
+ cated at the origin.Determine the
+ equations for velocity potential a
+ nd stream function.What are the ve
+ locity components at x=1 m,y=0.5 m
+ ?
+
+ Solution:
+
+ Vr=
+
+ 0.0284705
+
+ m/s
+
+ Vt=
+
+ 0.1423525
+
+ m/s
|