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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+// Scilab code Exa4.7.4: To determine the power produced by 100 milligram of Cf-252 : Page 191 (2011)
+N = 6.023e+023/252*0.1; // Number of nuclei in 100mg of Cf-252
+t_h = 2.62*365*24*3600; // Half life of Cf-252, s
+D_c = log(2)/t_h; // Decay constant, s^-1
+F_r = N*D_c; // Fission rate, fissions/s
+E = 210*1.6e-013; // Energy released during fission of one nucleus, J
+P = E*F_r; // Power released in fission of 100 milligram of Cf-252, W
+printf("\n Power released in fission of 100 milligram of Cf-252: %4.1f W", P)
+// Result
+// Power released in fission of 100 milligram of Cf-252: 67.4 W