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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /73/CH10/EX10.8 | |
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Diffstat (limited to '73/CH10/EX10.8')
| -rwxr-xr-x | 73/CH10/EX10.8/Example10_8.sci | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/73/CH10/EX10.8/Example10_8.sci b/73/CH10/EX10.8/Example10_8.sci new file mode 100755 index 000000000..3966390f3 --- /dev/null +++ b/73/CH10/EX10.8/Example10_8.sci @@ -0,0 +1,21 @@ +//Chapter 10_Special Purpose Amplifiers
+//Caption : LM4250 Parameters
+//Example10.8: The micropower programmable Op-Amp LM 4250 is supplied by 3 v sourse(absolute value) source.Determine the value of set resistor for Iset=0.1 uA if Rset is connected to (a)Vee and (b)ground. (c)determine the quiescent supply current and the quiescent power dissipation.
+clear;
+clc;
+//a)Solution:
+Vcc=3;//power supply in Volt
+Vee=-Vcc;//negative power supply in Volt
+Iset=0.1*10^-6;//bias setting current in A;
+Rset=(Vcc+abs(Vee)-0.5)/Iset;
+disp('mega Ohm',Rset/10^6,'The bias setting current resistor for Vee=-10 V is:')
+//b)Solution:
+clear Vee;
+Vee=0;//since Rset is connected to ground
+Rset=(Vcc+abs(Vee)-0.5)/Iset;
+disp('mega Ohm',Rset/10^6,'The bias setting current resistor for Vee=0 V is:')
+//c)Solution:
+Qcurrent=5*Iset;
+Qpower=(Vcc+3)*Qcurrent;//where abs(Vee)=3 V
+disp('uA',Qcurrent*10^6,'The quiescent current supply is:')
+disp('uW',Qpower*10^6,'The quiescent power dissipated is:')
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