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authorpriyanka2015-06-24 15:03:17 +0530
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+//Caption:Calculate (i)-value of repeller voltage V_r ,(ii)-beam current necessary to give gap voltage of 200V, (iii)-electronic efficiency
+//Exa:8.6
+clc;
+clear;
+close;
+e_m_ratio=1.759*10^11;//(e/m)
+V_o=500;//in volts
+R_sh=20*10^3;//in ohms
+f=8*10^9;//inHz
+w=2*%pi*f;
+n=2;//mode
+L=0.001;//spacing between repeller & cavity (in m)
+x=0.023;
+volt_diff=sqrt(V_o*(x));
+V_r=volt_diff+V_o;//repeller volatge
+Beeta_o=1;//Assuming
+J=0.582;
+V_1=200;//given (in volts)
+I_o=V_1/(R_sh*2*J);
+Theeta_o=2*%pi*f*J*10^6*2*10^-3*sqrt(V_o)/(1.579*10^11*(V_r+V_o));
+X=V_1*Theeta_o/(2*V_o);//X'
+j=0.84;//J(X')
+eff=[2*j/(2*%pi*2-%pi/2)]*100;
+disp(V_r,'Repeller voltage(in volts) =');
+disp(I_o,'Necessary beam current (in Amp.s) =');
+disp(eff,'Effeciency (in percentage) ='); \ No newline at end of file