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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Caption:Calculate the percentage resistance and reactance drops and the percentage of full load at which max efficiency will occur
+//Exa:3.27
+clc;
+clear;
+close;
+KVA=20;
+V1=1100;//in volts
+V2=220;//in volts
+a=V1/V2;
+P_i=175;//in watts
+R1=0.25;//in ohms
+R2=0.012;//in ohms
+X1=1.1;//in ohms
+X2=0.055;//in ohms
+R_O2=R2+R1/a^2;
+X_O2=X2+X1/a^2;
+I2=KVA*1000/V2;
+V_r=I2*R_O2*100/V2;
+disp(V_r,'Percentage Resistance drop (in %)=');
+V_re=I2*X_O2*100/V2;
+disp(V_re,'Percentage Reactance drop (in %)=');
+P_cu=I2^2*R_O2;
+x=sqrt(P_i/P_cu);
+disp(x*100,'Max Efficiency will occur at');
+disp('percent of full load'); \ No newline at end of file