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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Caption:Calculate (a)Efficiency at full load and at unity power factor (b)Efficiency at half load and 0.8 power factor (c)Efficiency at 75 percent of load and 0.7 power factor (d)load KVA at which maximum efficiency will occcur (e)maximum efficiency at 0.85 power factor
+//Exa:3.22
+clc;
+clear;
+close;
+KVA=100;
+P_cu=1200;//in watts
+P_i=960;//in watts
+x1=1;
+pf1=1;
+P_o_1=x1*KVA*pf1*1000;
+Eff_1=P_o_1/(P_o_1+P_i+x1^2*P_cu);
+disp(Eff_1*100,'(a)Efficiency at full load and at unity power factor (in %)=');
+x2=0.5;
+pf2=0.8;
+P_o_2=x2*KVA*1000*pf2;
+Eff_2=P_o_2/(P_o_2+P_i+x2^2*P_cu);
+disp(Eff_2*100,'(b)Efficiency at half load and at 0.8 power factor (in %)=');
+x3=0.75;
+pf3=0.7;
+P_o_3=x3*KVA*1000*pf3;
+Eff_3=P_o_3/(P_o_3+P_i+x3^2*P_cu);
+disp(Eff_3*100,'(c) Efficiency at 75 percent of load and 0.7 power factor(in %)=');
+KVA_max=KVA*sqrt(P_i/P_cu);
+disp(KVA_max,'(d)load KVA at which maximum efficiency will occcur (in KVA)=');
+Eff_max=KVA_max*1000*0.85/(KVA_max*1000*0.85+2*P_i);
+disp(Eff_max*100,'(e)maximum efficiency at 0.85 power factor(in %)=') \ No newline at end of file