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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Caption:Determine the (a)Load at which max efficiency occurs and value of max efficiency (b)New core loss and Cu loss
+//Exa:3.17
+clc;
+clear;
+close;
+KVA=20;
+P_i=250;//in watts
+P_cu=500;//in watts
+x=sqrt(P_i/P_cu);
+disp(x*100,'(a)Max efficiency will occur at');
+disp('Percent of full load');
+P_o=x*KVA*1000;
+Eff=P_o/(P_o+P_i+P_i);
+disp(Eff*100,'Maximum Efficiency (in %)=');
+P_cu_n=(P_i+P_cu)/(0.85^2+1);
+P_i_n=P_i+P_cu-P_cu_n;
+disp(P_i_n,'(b)Core Loss (in watts)=');
+disp(P_cu_n,' Copper Loss (in watts)=') \ No newline at end of file