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authorpriyanka2015-06-24 15:03:17 +0530
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+// Example 6.7 : Application of miller's theorem
+
+// 6.7a
+// By miller's theorem
+Z=1000*10^3; // (ohm)
+K=-100; // (V/V)
+R_sig=10*10^3; // (ohm)
+Z_1=Z/(1-K);
+disp(Z_1,"Z_1 (ohm)")
+Z_2=Z/(1-(1/K));
+disp(Z_2,"Z_2 (ohm)")
+VobyVsig=-100*Z_1/(Z_1+R_sig); // VobyVsig=(V_o/V_sig)
+disp(VobyVsig,"(V_o/V_sig) (V/V)")
+
+//6.7b
+// Applying miller's theorem
+f_3dB=1/(2*%pi*1.01*10^-6);
+disp(f_3dB,"f_3dB (Hz)") \ No newline at end of file