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authorpriyanka2015-06-24 15:03:17 +0530
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+// Example 5.13 : Design of bias network of the amplifier
+I_E=1*10^-3; // (A)
+V_CC=12; // (V)
+B=100; // beta value
+V_B=4; // (V)
+V_BE=0.7; // (V)
+R1=80; // (ohm)
+R2=40; // (ohm)
+V_C=8; // (V)
+V_E=V_B-V_BE;
+disp(V_E,"Emitter voltage (V)")
+R_E=V_E/I_E;
+disp(R_E,"Emitter resistance (ohm)")
+I_E=(V_B-V_BE)/(R_E+(R1*R2/(R1+R2))/(B+1));
+disp(I_E,"more accurate value for I_E (A) for R1=80 ohm and R2=40 ohm")
+R1=8; // (ohm)
+R2=4; // (ohm)
+I_E=(V_B-V_BE)/(R_E+(R1*R2/(R1+R2))/(B+1));
+disp(I_E,"more accurate value for I_E (A) for R1=8 ohm and R2=4 ohm")
+R_C=(V_CC-V_C)/I_E; // I_E=I_C
+disp(R_C,"Collector resistor (ohm)") \ No newline at end of file