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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+
+// Example: 2.17
+// Page: 62
+
+printf("Example: 2.17 - Page: 64\n\n");
+
+// Solution
+
+//*****Data*****//
+D1 = 1;// [m]
+P1 = 120;// [kPa]
+P2 = 360;// [kPa]
+// P = k*D^3
+//***************//
+
+k = P1/D1^3;// [proportionality constant]
+D2 = (P2/k)^(1/3);// [m]
+// Work done by the gas inside the balloon can be estimated as:
+// W = integral(P*dV);
+// W = integral((k*D^3)*d((4/3)*%pi*r^3);
+// W = (%pi*k/6)*integral((D^3)*d(D^3));
+// W = (%pi*k/12)*(D2^6 - D1^6);
+W = (%pi*k/12)*(D2^6 - D1^6);// [kJ]
+printf("Workdone by the gas is %.2f kJ\n",W); \ No newline at end of file