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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /647/CH2/EX2.14 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
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Diffstat (limited to '647/CH2/EX2.14')
| -rwxr-xr-x | 647/CH2/EX2.14/Example2_14.sce | 84 |
1 files changed, 84 insertions, 0 deletions
diff --git a/647/CH2/EX2.14/Example2_14.sce b/647/CH2/EX2.14/Example2_14.sce new file mode 100755 index 000000000..e41d92d5c --- /dev/null +++ b/647/CH2/EX2.14/Example2_14.sce @@ -0,0 +1,84 @@ +clear;
+clc;
+
+// Example: 2.14
+// Page: 60
+
+printf("Example: 2.14 - Page: 60\n\n");
+
+// Solution
+
+//*****Data*****//
+n = 1;// [mol]
+T1 = 610;// [K]
+P1 = 10^6;// [N/square m]
+T2 = 310;// [K]
+P2 = 10^5;// [N/square m]
+Cv = 20.78;// [J/mol K]
+//*************//
+
+R = 8.314;// [J/K mol]
+
+// Step 1: Isothermal Expansion Of Ideal Gas:
+printf("Step 1: Isothermal Expansion Of Ideal Gas\n")
+T1 = 610;// [K]
+P1 = 10^6;// [N/square m]
+P2 = 10^5;// [N/square m]
+// Work done:
+W1 = 2.303*n*R*T1*log10(P1/P2);// [J/mol]
+// For isothermal expansion:
+delta_E1 = 0;// [J/mol]
+// From first law of thermodynamics:
+Q1 = delta_E1 + W1;// [J/mol]
+printf("delta_E for Step 1 is %d J/mol\n",delta_E1);
+printf("Q for step 1 is %.2f J/mol\n",Q1);
+printf("W for step 1 is %.2f J/mol\n",W1);
+printf("\n");
+
+// Step 2: Adiabatic Expansion of ideal gas:
+printf("Step 2: Adiabatic Expansion of ideal gas\n")
+Q2 = 0;// [J/mol]
+delta_E2 = Cv*(T2 - T1);// [J/mol]
+// From first law of thermodynamics:
+W2 = Q2 - delta_E2;// [J/mol]
+printf("delta_E for Step 2 is %d J/mol\n",delta_E2);
+printf("Q for step 2 is %.2f J/mol\n",Q2);
+printf("W for step 2 is %.2f J/mol\n",W2);
+printf("\n");
+
+// Step 3: Isothermal Compression Of Ideal Gas:
+printf("Step 3: Isothermal Compression Of Ideal Gas\n")
+T2 = 310;// [K]
+P1 = 10^5;// [N/square m]
+P2 = 10^6;// [N/square m]
+// Work done:
+W3 = 2.303*n*R*T2*log10(P1/P2);// [J/mol]
+// For isothermal expansion:
+delta_E3 = 0;// [J/mol]
+// From first law of thermodynamics:
+Q3 = delta_E3 + W3;// [J/mol]
+printf("delta_E for Step 3 is %d J/mol\n",delta_E3);
+printf("Q for step 3 is %.2f J/mol\n",Q3);
+printf("W for step 3 is %.2f J/mol\n",W3);
+printf("\n");
+
+// Step 4: Adiabatic Compression of ideal gas:
+printf("Step 4: Adiabatic Compression of ideal gas\n")
+T1 = 310;// [K]
+T2 = 610;// [K]
+Q4 = 0;// [J/mol]
+delta_E4 = Cv*(T2 - T1);// [J/mol]
+// From first law of thermodynamics:
+W4 = Q4 - delta_E4;// [J/mol]
+printf("delta_E for Step 4 is %d J/mol\n",delta_E4);
+printf("Q for step 4 is %.2f J/mol\n",Q4);
+printf("W for step 4 is %.2f J/mol\n",W4);
+printf("\n");
+
+// Net work done for the complete cycle:
+W = W1 + W2 + W3 + W4;// [J/mol]
+printf("Net Work done for the complete cycle is %.2f J/mol\n",W);
+
+// The efficiency of the cycle is given by:
+eta = 1- T1/T2;
+printf("The efficiency of the cycle is %.2f\n",eta);
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