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authorpriyanka2015-06-24 15:03:17 +0530
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+clear;
+clc;
+
+// Example: 12.3
+// Page: 479
+
+printf("Example: 12.3 - Page: 479\n\n");
+
+// Solution
+
+//*****Data******//
+// Reaction: C2H5OH(g) + (1/2)O2(g) = CH3CHO(g) + H2O(g)
+Temp = 298;// [K]
+G_CH3CHO = -133.978;// [kJ]
+G_H2O = -228.60;// [kJ]
+G_C2H5OH = -174.883;// [kJ]
+R = 8.314;// [J/mol K]
+//***************//
+
+G_O2 = 0;// [kJ]
+G_rkn = G_CH3CHO + G_H2O -(G_C2H5OH + G_O2);// [kJ]
+G_rkn = G_rkn*1000;// [J]
+if G_rkn < 0
+ printf("Reaction is feasible\n");
+ K = exp(-(G_rkn/(R*Temp)));
+ printf("Equilibium Constant is %.3e",K);
+else
+ printf("Reaction is not feasible\n");
+end \ No newline at end of file