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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /635/CH8/EX8.7/Ch08Ex7.sci | |
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diff --git a/635/CH8/EX8.7/Ch08Ex7.sci b/635/CH8/EX8.7/Ch08Ex7.sci new file mode 100755 index 000000000..5f87c26da --- /dev/null +++ b/635/CH8/EX8.7/Ch08Ex7.sci @@ -0,0 +1,17 @@ +// Scilab Code Ex8.7 Calculation of wavelengths of tin and barium using Moseley's law Page-257 (2010) +Z_Fe = 26; // Atomic number of iron +Z_Pt = 78; // Atomic number of platinum +Z_Sn = 50; // Atomic number of tin +Z_Ba = 56; // Atomic number of barium +b = 1; // Mosley's constant for K-series +lambda_Fe = 1.93e-010; // Wavelength of K_alpha line of Fe +lambda_Pt = 0.19e-010; // Wavelength of K_alpha line of Pt +// From Moseley's Law, +// f = a*(Z-1)^2. This implies lambda = C*1/(Z-1)^2 +// so that lambda_Fe = C*1/(Z_Fe-1)^2 and lambda_Sn = C*1/(Z_Sn-1)^2 +// Dividing lambda_Sn by lambda_Fe and solving for lambda_Sn +lambda_Sn = (Z_Fe-1)^2/(Z_Sn-1)^2*lambda_Fe; // Wavelength of K_alpha line for tin, m +lambda_Ba = (Z_Pt-1)^2/(Z_Ba-1)^2*lambda_Pt; // Wavelength of K_alpha line for barium, m +printf("\nThe wavelengths of tin and barium = %3.1f angstrom and %4.2f angstrom respectively", lambda_Sn/1D-10, lambda_Ba/1D-10); +// Result +// The wavelengths of tin and barium = 0.5 angstrom and 0.37 angstrom respectively
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