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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//clc()
+F = 100;//kg
+xf = 0.25;
+x2 = 7/107;
+P1 = 10;//%
+W3 = P1 * F * (1-xf)/100;//(W3 - weight of water evaporated)
+// let W1 and W2 be weight of crystal and weight of mother liquor remaining after crystallization resp.,
+//F = W1 + W2 + W3
+//100 = W1 + W2 + 7.5
+//solute balance gives, F*xf = W1*x1 + W2*x2
+//100*0.25 = W1*1+W2 * 0.0654
+W2 = (F - W3 - F*xf)/(1-x2);
+W1 = F - W3 - W2;
+disp("kg",W1,,,"yeild of the crystals = ") \ No newline at end of file