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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//clc()
+//F = feed, E = extract, S = solvent, R = Raffinate
+xwaterF = 0.7;//Feed
+xalcoholF = 0.3;
+xwaterR = 0.71;//raffinate
+xalcoholR = 0.281;
+xethyR = 0.009;
+xwaterE = 0.008;//Extract
+xalcoholE = 0.052;
+xethyE = 0.94;
+//Total balance, R + E = F + S
+F = 100;//kg
+//R + E = 100 + S (1)
+//Isopropyl balance, xalcoholR * R + xalcoholE*E = xalcoholF * F
+//0.281*R + 0.052 * E = 30 (2)
+//Ethylene tetra chloride balance, xethyR * R + xethyE * E = S
+//0.009*R + 0.94*E = S (3)
+//Solving equation 1, 2 and 3 simultaneously, we get,
+S = 45.1;
+E = 47.04;
+R = 98.06;
+disp("kg",S,"(a)Amount of solvent used = ")
+disp("kg",E,"(b)Amount of extract = ")
+disp("kg",R," Amount of raffinate = ")
+mextracted = E * xalcoholE;
+P1 = mextracted * 100 / (F * xalcoholF);
+disp("%",P1,"(c)Percent of isopropyl alcohol extracted = ")