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+//clc()

+P1 = 75;//kPa

+T1 = 573;//K

+Tvap = 365;//K

+Tbasis = 273;//K

+//Since, the boiling point of water at 75kPa is 375K, the vapour at 573K is superheated;

+H1 = 3075;//kJ/kg

+Cliq = 4.2;//kJ/kgK

+Cvap = 1.97;//kJ/kg/K

+m = 1;//kg

+//let assume converting liq. water into superheated stream occurs in 3 steps,

+//step1 - water is heated from 273K to 365 K at constant pressure,enthalpy change is the heat required to change the temperature,

+Hc1 = m*Cliq * ( Tvap - Tbasis );

+//step2 - the liq is vapurized at constant pressure and constant temperature, enthalpy change is equal to the heat of vapourisation, say Hc2

+//step3 - the saturated vapour at 365K is heated to 573K at constant pressure, the enthalpy change is the heat required to raise the temperature

+Hc3 = m*Cvap*(T1 - Tvap);

+//total enthalpy = 3075 = Hc1 + Hc2 + Hc3, therefore

+Hc2 = H1 - Hc1 - Hc3;

+disp("kJ/kg",Hc2,"Heat of vapourisation = ")
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