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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+clear
+clc
+//Example 9.7 RESISTANCE FORCE WITH TRIPPED BOUNDARY LAYER
+L=6; //[m]
+B=3; //[m]
+mu=1.81*10^-5; //[N.s/m^2]
+rho=1.2; //[Kg/m^3]
+Uo=20; //[m/s]
+ReL=rho*Uo*L/mu //Reynold's number
+//Average shear-stress coefficient
+Cf=0.032/ReL^(1/7)
+A=L*B //area [m^2]
+//Resistance force
+Fs=2*Cf*A*rho*(Uo^2)/2 //[N]
+printf("\nTotal shear resistance on both sides of plate = %.1f N.\n",Fs) \ No newline at end of file