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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
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diff --git a/611/CH14/EX14.1/Chap14_Ex1_R1.sce b/611/CH14/EX14.1/Chap14_Ex1_R1.sce new file mode 100755 index 000000000..d2e04e283 --- /dev/null +++ b/611/CH14/EX14.1/Chap14_Ex1_R1.sce @@ -0,0 +1,26 @@ +// Y.V.C.Rao ,1997.Chemical Engineering Thermodynamics.Universities Press,Hyderabad,India.
+
+//Chapter-14,Example 1,Page 489
+//Title: Standard Gibbs free energy change and equilibrium constant
+//================================================================================================================
+clear
+clc
+
+//INPUT
+//The water gas shift reaction is given by : CO2(g)+H2(g)--->CO(g)+H2O(g)
+T=298.15;//temperature in K
+del_Gf=[-137.327;-228.600;-394.815;0];//the standard Gibbs free energy of formation of CO(g),H2O(g),CO2(g) and H2(g) in kJ
+n=[1;1;-1;-1];//stoichiometric coefficients of CO(g),H2O(g),CO2(g) and H2(g) respectively (no unit)
+R=8.314;//universal gas constant in J/molK
+
+//CALCULATION
+//calculation of the standard Gibbs free energy of reaction at 298.15K using Eq.(14.1) in kJ
+del_G=(n(1,:)*del_Gf(1,:))+(n(2,:)*del_Gf(2,:))+(n(3,:)*del_Gf(3,:))+(n(4,:)*del_Gf(4,:));
+Ka=exp((-(del_G*10^3))/(R*T));//calculation of the equilibrium constant using Eq.(14.9) (no unit)
+
+//OUTPUT
+mprintf('The standard Gibbs free energy of the water gas shift reaction at 298.15K=%0.3f kJ \n',del_G);
+mprintf('The equilibrium constant of the water gas shift reaction at 298.15K=%0.3e \n',Ka);
+
+//===============================================END OF PROGRAM===================================================
+
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