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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH6/EX6.13 | |
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initial commit / add all books
Diffstat (limited to '608/CH6/EX6.13')
-rwxr-xr-x | 608/CH6/EX6.13/6_13.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/608/CH6/EX6.13/6_13.sce b/608/CH6/EX6.13/6_13.sce new file mode 100755 index 000000000..40c3caced --- /dev/null +++ b/608/CH6/EX6.13/6_13.sce @@ -0,0 +1,20 @@ +//Problem 6.13: Capacitances of 3 μF, 6 μF and 12 μF are connected in series across a 350 V supply. Calculate (a) the equivalent circuit capacitance, (b) the charge on each capacitor and (c) the pd across each capacitor.
+
+//initializing the variables:
+C1 = 3E-6; // in Farads
+C2 = 6E-6; // in Farads
+C3 = 12E-6; // in Farads
+Vt = 350; // in Volts
+
+//calculation:
+// in series
+Cs = 1/[(1/C1) + (1/C2) + (1/C3)]
+Qt = Vt*Cs
+V1 = Qt/C1
+V2 = Qt/C2
+V3 = Qt/C3
+
+printf("\n\nResult\n\n")
+printf("\n (a)Equivalent Capacitance in Series %.2E F",Cs)
+printf("\n (b)Charge on each capacitors (C1, C2, C3) %.2E C",Qt)
+printf("\n (b)P.d Across each capacitors (C1, C2, C3) %.0f V, %.0f V, %.0f V respectively",V1, V2, V3)
\ No newline at end of file |