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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH5/EX5.01 | |
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initial commit / add all books
Diffstat (limited to '608/CH5/EX5.01')
-rwxr-xr-x | 608/CH5/EX5.01/5_01.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/608/CH5/EX5.01/5_01.sce b/608/CH5/EX5.01/5_01.sce new file mode 100755 index 000000000..6caaf286c --- /dev/null +++ b/608/CH5/EX5.01/5_01.sce @@ -0,0 +1,21 @@ +//Problem 5.01: For the circuit shown in Figure 5.2, determine (a) the battery voltage V, (b) the total resistance of the circuit, and (c) the values of resistance of resistors R1, R2 and R3, given that the p.d.’s across R1, R2 and R3 are 5 V, 2 V and 6 V respectively.
+
+//initializing the variables:
+V1 = 5; // in volts
+V2 = 2; // in volts
+V3 = 6; // in volts
+I = 4; // in Amperes
+
+//calculation:
+Vt = V1 + V2 + V3
+Rt = Vt/I
+R1 = V1/I
+R2 = V2/I
+R3 = V3/I
+
+printf("\n\nResult\n\n")
+printf("\n (a) Total Voltage %.0f Volts(V)",Vt)
+printf("\n (b)Total Resistance %.2f Ohms",Rt)
+printf("\n (c)Resistance(R1) %.2f Ohms",R1)
+printf("\n (c)Resistance(R2) %.1f Ohms",R2)
+printf("\n (c)Resistance(R3) %.1f Ohms",R3)
\ No newline at end of file |