diff options
| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH42/EX42.01/42_01.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '608/CH42/EX42.01/42_01.sce')
| -rwxr-xr-x | 608/CH42/EX42.01/42_01.sce | 21 |
1 files changed, 21 insertions, 0 deletions
diff --git a/608/CH42/EX42.01/42_01.sce b/608/CH42/EX42.01/42_01.sce new file mode 100755 index 000000000..d776ee867 --- /dev/null +++ b/608/CH42/EX42.01/42_01.sce @@ -0,0 +1,21 @@ +//Problem 42.01: Determine the cut-off frequency and the nominal impedance of each of the low-pass filter sections shown in Figure 42.19.
+
+//initializing the variables:
+L1 = 2*100E-3; // in Henry
+C1 = 0.2E-6; // in Fareads
+L2 = 0.4; // in Henry
+C2 = 2*200E-12; // in Fareads
+
+//calculation:
+//cut-off frequency
+fc1 = 1/(%pi*(L1*C1)^0.5)
+//nominal impedance
+R01 = (L1/C1)^0.5
+//cut-off frequency
+fc2 = 1/(%pi*(L2*C2)^0.5)
+//nominal impedance
+R02 = (L2/C2)^0.5
+
+printf("\n\n Result \n\n")
+printf("\n cut-off frequency %.0f Hz and the nominal impedance is %.0f ohm ",fc1, R01)
+printf("\n cut-off frequency %.0f Hz and the nominal impedance is %.0f ohm ",fc2, R02)
\ No newline at end of file |