updated the code

1 files changed, 19 insertions, 18 deletions

diff --git a/608/CH38/EX38.06/38_06.sce b/608/CH38/EX38.06/38_06.sce
index e0cdac3ae..4c850ce53 100755
--- a/608/CH38/EX38.06/38_06.sce
+++ b/608/CH38/EX38.06/38_06.sce
@@ -1,19 +1,20 @@
-//Problem 38.06: The core of a transformer operating at 50 Hz has an eddy current loss of 100 W/m3 and the core laminations have a thickness of 0.50 mm. The core is redesigned so as to operate with the same eddy current loss but at a different voltage and at a frequency of 250 Hz. Assuming that at the new voltage the maximum flux density is one-third of its original value and the resistivity of the core remains unaltered, determine the necessary new thickness of the laminations.

-

-//initializing the variables:

-Pe = 100; // in W/m3

-f1 = 50; // in Hz

-t1 = 0.0005; // in m

-x = 1/3;

-f2 = 250; // in Hz

-

-//calculation: 

-//Pe = ke*(Bm1*f1*t1)^2

-//Hence, at 50 Hz frequency

-ke = Pe/(Bm1*f1*t1)^2

-//At 250 Hz frequency

-Bm2 = x*Bm1

-t2 = ((Pe/ke)^0.5)/(Bm2*f2)

-

-printf("\n\n Result \n\n")

+//Problem 38.06: The core of a transformer operating at 50 Hz has an eddy current loss of 100 W/m3 and the core laminations have a thickness of 0.50 mm. The core is redesigned so as to operate with the same eddy current loss but at a different voltage and at a frequency of 250 Hz. Assuming that at the new voltage the maximum flux density is one-third of its original value and the resistivity of the core remains unaltered, determine the necessary new thickness of the laminations.
+
+//initializing the variables:
+Pe = 100; // in W/m3
+f1 = 50; // in Hz
+t1 = 0.0005; // in m
+x = 1/3;
+f2 = 250; // in Hz
+//Assigning a sample value to Bm1
+Bm1 = 1;
+//calculation: 
+//Pe = ke*(Bm1*f1*t1)^2
+//Hence, at 50 Hz frequency
+ke = Pe/(Bm1*f1*t1)^2
+//At 250 Hz frequency
+//Bm2 = x*Bm1
+t2 = ((Pe/ke)^0.5)/(Bm2*f2)
+
+printf("\n\n Result \n\n")
 printf("\nlamination thickness is %.2Em",t2)
\ No newline at end of file