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+//Problem 35.06: Determine, for the network shown in Figure 35.8, (a) the values of R and X that will result in maximum power being transferred across terminals AB, and (b) the value of the maximum power.

+

+//initializing the variables:

+rv = 100; // in volts

+thetav = 30; // in degrees

+R1 = 5; // in ohm

+R2 = 5; // in ohm

+R3 = %i*10; // in ohm

+

+//calculation: 

+//voltage

+V = rv*cos(thetav*%pi/180) + %i*rv*sin(thetav*%pi/180)

+//Resistance R and reactance X are removed from the network as shown in Figure 35.9

+//P.d. across AB,

+E = ((R2 + R3)/(R1 + R2 + R3))*V

+//With the source removed the impedance, z, ‘looking in’ at terminals AB is given by:

+z = (R2 + R3)*R1/(R1 + R2 + R3)

+//The equivalent Th´evenin circuit is shown in Figure 35.10. From condition 3, maximum power transfer is achieved when X = -1*imag(z) and R = real(z)

+X = -1*imag(z)

+R = real(z)

+Z = R + %i*X

+//Current I flowing in the load is given by

+I = E/(z + Z)

+Imag = (real(I)^2 + imag(I)^2)^0.5

+//maximum power transferred,

+P = R*Imag^2

+

+printf("\n\n Result \n\n")

+printf("\n (a)maximum power transfer occurs when R is %.2f ohm and X is %.2f ohm",R, X)

+printf("\n (b) maximum power delivered is %.0f W",P)
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