initial commit / add all books

19 files changed, 254 insertions, 0 deletions

diff --git a/608/CH2/EX2.01/2_01.sce b/608/CH2/EX2.01/2_01.sce
new file mode 100755
index 000000000..ee51783f1
--- /dev/null
+++ b/608/CH2/EX2.01/2_01.sce
@@ -0,0 +1,11 @@
+//Problem 2.01: What current must flow if 0.24 coulombs is to be transferred in 15 ms?

+

+//initializing the variables:

+Q = 0.24; // in Coulomb

+t = 0.015; // in sec

+

+//calculation:

+I = Q/t

+

+printf("\n\nResult\n\n")

+printf("\nCurrent(I): %.0f Ampere(A)\n",I)
\ No newline at end of file
diff --git a/608/CH2/EX2.02/2_02.sce b/608/CH2/EX2.02/2_02.sce
new file mode 100755
index 000000000..bcdb5b4e1
--- /dev/null
+++ b/608/CH2/EX2.02/2_02.sce
@@ -0,0 +1,11 @@
+//Problem 2.02: If a current of 10 A flows for four minutes, find the quantity of electricity transferred.

+

+//initializing the variables:

+I = 10; // in Ampere

+t = 240; // in sec

+

+//calculation:

+Q = I*t

+

+printf("\n\nResult\n\n")

+printf("\nCharge(Q): %.0f Coulomb(C)\n",Q)
\ No newline at end of file
diff --git a/608/CH2/EX2.03/2_03.sce b/608/CH2/EX2.03/2_03.sce
new file mode 100755
index 000000000..91c2f5255
--- /dev/null
+++ b/608/CH2/EX2.03/2_03.sce
@@ -0,0 +1,11 @@
+//Problem 2.03: The current flowing through a resistor is 0.8 A when a p.d. of 20 V is applied. Determine the value of the resistance.

+

+//initializing the variables:

+I = 0.8; // in Ampere

+V = 20; // in Volts

+

+//calculation:

+R = V/I

+

+printf("\n\nResult\n\n")

+printf("\nResistance(R): %.0f Ohms\n",R)
\ No newline at end of file
diff --git a/608/CH2/EX2.04/2_04.sce b/608/CH2/EX2.04/2_04.sce
new file mode 100755
index 000000000..b20cc31ce
--- /dev/null
+++ b/608/CH2/EX2.04/2_04.sce
@@ -0,0 +1,11 @@
+//Problem 2.04: Determine the p.d. which must be applied to a 2 kohm resistor in order that a current of 10 mA may flow.

+

+//initializing the variables:

+I = 0.010; // in Ampere

+R = 2000; // in ohms

+

+//calculation:

+V = I*R

+

+printf("\n\nResult\n\n")

+printf("\np.d.(V): %.0f Volts(V)\n",V)
\ No newline at end of file
diff --git a/608/CH2/EX2.05/2_05.sce b/608/CH2/EX2.05/2_05.sce
new file mode 100755
index 000000000..482ea9946
--- /dev/null
+++ b/608/CH2/EX2.05/2_05.sce
@@ -0,0 +1,11 @@
+//Problem 2.05: A coil has a current of 50 mA flowing through it when the applied voltage is 12 V. What is the resistance of the coil?

+

+//initializing the variables:

+I = 0.050; // in Ampere

+V = 12; // in Volts

+

+//calculation:

+R = V/I

+

+printf("\n\nResult\n\n")

+printf("\nResistance(R): %.0f Ohms\n",R)
\ No newline at end of file
diff --git a/608/CH2/EX2.06/2_06.sce b/608/CH2/EX2.06/2_06.sce
new file mode 100755
index 000000000..54213d54c
--- /dev/null
+++ b/608/CH2/EX2.06/2_06.sce
@@ -0,0 +1,16 @@
+//Problem 2.06: A 100 V battery is connected across a resistor and causes a current of 5 mA to flow. Determine the resistance of the resistor. If the voltage is now reduced to 25 V, what will be the new value of the current flowing?

+

+//initializing the variables:

+I = 0.005; // in Ampere

+V1 = 100; // in Volts

+V2 = 25; // in Volts

+

+//calculation:

+//resistance

+R = V1/I

+//Current when voltage is reduced to 25 V,

+I = V2/R

+

+printf("\n\nResult\n\n")

+printf("\nResistance(R): %.0f Ohms",R)

+printf("\n Current when voltage is reduced to 25 V is %.2E A",I)
\ No newline at end of file
diff --git a/608/CH2/EX2.07/2_07.sce b/608/CH2/EX2.07/2_07.sce
new file mode 100755
index 000000000..82a36b2a0
--- /dev/null
+++ b/608/CH2/EX2.07/2_07.sce
@@ -0,0 +1,14 @@
+//Problem 2.07: What is the resistance of a coil which draws a current of (a) 50 mA and (b) 200 μA from a 120 V supply?

+

+//initializing the variables:

+I1 = 0.050; // in Ampere

+I2 = 200E-6; // in Ampere

+V = 120; // in Volts

+

+//calculation:

+R1 = V/I1

+R2 = V/I2

+

+printf("\n\nResult\n\n")

+printf("\nResistance(R1): %.0f Ohms",R1)

+printf("\nResistance(R2): %.0f Ohms\n",R2)
\ No newline at end of file
diff --git a/608/CH2/EX2.08/2_08.sce b/608/CH2/EX2.08/2_08.sce
new file mode 100755
index 000000000..1484ef851
--- /dev/null
+++ b/608/CH2/EX2.08/2_08.sce
@@ -0,0 +1,13 @@
+//Problem 2.08: A 100 W electric light bulb is connected to a 250 V supply. Determine (a) the current flowing in the bulb, and (b) the resistance of the bulb.

+

+//initializing the variables:

+P = 100; // in Watt

+V = 250; // in Volts

+

+//calculation:

+I = P/V

+R = V/I

+

+printf("\n\nResult\n\n")

+printf("\nCurrent(I): %.1f Ampere(A)",I)

+printf("\nResistance(R): %.0f Ohms\n",R)
\ No newline at end of file
diff --git a/608/CH2/EX2.09/2_09.sce b/608/CH2/EX2.09/2_09.sce
new file mode 100755
index 000000000..edceb587e
--- /dev/null
+++ b/608/CH2/EX2.09/2_09.sce
@@ -0,0 +1,11 @@
+//Problem 2.09: Calculate the power dissipated when a current of 4 mA flows through a resistance of 5 k

+

+//initializing the variables:

+I = 0.004; // in ampere

+R = 5000; // in ohms

+

+//calculation:

+P = I*I*R 

+

+printf("\n\nResult\n\n")

+printf("\nPower(P): %.2f Watt(W)\n",P)
\ No newline at end of file
diff --git a/608/CH2/EX2.10/2_10.sce b/608/CH2/EX2.10/2_10.sce
new file mode 100755
index 000000000..b26bb40dd
--- /dev/null
+++ b/608/CH2/EX2.10/2_10.sce
@@ -0,0 +1,13 @@
+//Problem 2.10: An electric kettle has a resistance of 30. What current will flow when it is connected to a 240 V supply? Find also the power rating of the kettle.

+

+//initializing the variables:

+V = 240; // in Volts

+R = 30; // in ohms

+

+//calculation:

+I = V/R

+P = V*I

+

+printf("\n\nResult\n\n")

+printf("\nCurrent(I): %.0f Ampere(A)",I)

+printf("\nPower(P): %.0f Watt(W)\n",P)
\ No newline at end of file
diff --git a/608/CH2/EX2.11/2_11.sce b/608/CH2/EX2.11/2_11.sce
new file mode 100755
index 000000000..9a5eabe4a
--- /dev/null
+++ b/608/CH2/EX2.11/2_11.sce
@@ -0,0 +1,13 @@
+//Problem 2.11: A current of 5 A flows in the winding of an electric motor, the resistance of the winding being 100. Determine (a) the p.d. across the winding, and (b) the power dissipated by the coil.

+

+//initializing the variables:

+I = 5; // in ampere

+R = 100; // in ohms

+

+//calculation:

+V = I*R

+P = I*R*I

+

+printf("\n\nResult\n\n")

+printf("\np.d(V): %.0f Volts(V)",V)

+printf("\nPower(P): %.0f Watt(W)\n",P)
\ No newline at end of file
diff --git a/608/CH2/EX2.12/2_12.sce b/608/CH2/EX2.12/2_12.sce
new file mode 100755
index 000000000..cdd3a7a43
--- /dev/null
+++ b/608/CH2/EX2.12/2_12.sce
@@ -0,0 +1,15 @@
+//Problem 2.12: The current/voltage relationship for two resistors A and B is as shown in Figure 2.5. Determine the value of the resistance of each resistor.

+

+//initializing the variables:

+I1 = 0.020; // in ampere

+V1 = 20; // in Volts

+I2 = 0.005; // in ampere

+V2 = 16; // in Volts

+

+//calculation:

+R1 = V1/I1

+R2 = V2/I2

+

+printf("\n\nResult\n\n")

+printf("\nResistance(R1): %.0f Ohms",R1)

+printf("\nResistance(R2): %.0f Ohms\n",R2)
\ No newline at end of file
diff --git a/608/CH2/EX2.13/2_13.sce b/608/CH2/EX2.13/2_13.sce
new file mode 100755
index 000000000..a0d96c6da
--- /dev/null
+++ b/608/CH2/EX2.13/2_13.sce
@@ -0,0 +1,13 @@
+//Problem 2.13: The hot resistance of a 240 V filament lamp is 960. Find the current taken by the lamp and its power rating.

+

+//initializing the variables:

+V = 240; // in Volts

+R = 960; // in ohms

+

+//calculation:

+I = V/R

+P = I*V

+

+printf("\n\nResult\n\n")

+printf("\nCurrent(I): %.2f Ampere(A)",I)

+printf("\nPower(P): %.0f Watt(W)\n",P)
\ No newline at end of file
diff --git a/608/CH2/EX2.14/2_14.sce b/608/CH2/EX2.14/2_14.sce
new file mode 100755
index 000000000..f2c22469e
--- /dev/null
+++ b/608/CH2/EX2.14/2_14.sce
@@ -0,0 +1,16 @@
+//Problem 2.14: A 12 V battery is connected across a load having a resistance of 40ohms. Determine the current flowing in the load, the power consumed and the energy dissipated in 2 minutes.

+

+//initializing the variables:

+V = 12; // in Volts

+R = 40; // in ohms

+t = 120; // in sec

+

+//calculation:

+I = V/R

+P = I*V

+E = P*t

+

+printf("\n\nResult\n\n")

+printf("\nCurrent(I): %.1f Ampere(A)",I)

+printf("\nPower(P): %.1f Watt(W)",P)

+printf("\nEnergy(E): %.0f Joule(J)\n",E)
\ No newline at end of file
diff --git a/608/CH2/EX2.15/2_15.sce b/608/CH2/EX2.15/2_15.sce
new file mode 100755
index 000000000..5489f0ba1
--- /dev/null
+++ b/608/CH2/EX2.15/2_15.sce
@@ -0,0 +1,12 @@
+//Problem 2.15: A source of e.m.f. of 15 V supplies a current of 2 A for six minutes. How much energy is provided in this time?

+

+//initializing the variables:

+V = 15; // in Volts

+I = 2; // in ampere

+t = 360; // in sec

+

+//calculation:

+E = V*I*t

+

+printf("\n\nResult\n\n")

+printf("\nEnergy(E): %.0f Joule(J)\n",E)
\ No newline at end of file
diff --git a/608/CH2/EX2.16/2_16.sce b/608/CH2/EX2.16/2_16.sce
new file mode 100755
index 000000000..64388ba2e
--- /dev/null
+++ b/608/CH2/EX2.16/2_16.sce
@@ -0,0 +1,15 @@
+//Problem 2.16: Electrical equipment in an office takes a current of 13 A from a 240 V supply. Estimate the cost per week of electricity if the equipment is used for 30 hours each week and 1 kWh of energy costs 7p?

+

+//initializing the variables:

+V = 240; // in Volts

+I = 13; // in ampere

+t = 30; // in hours

+p = 7; // in paise per kWh

+

+//calculation:

+P = V*I

+E = P*t/1000 // in kWh

+C = E*p

+

+printf("\n\nResult\n\n")

+printf("\nCost per week: %.1f Paise(p)\n",C)
\ No newline at end of file
diff --git a/608/CH2/EX2.17/2_17.sce b/608/CH2/EX2.17/2_17.sce
new file mode 100755
index 000000000..72d9d7b99
--- /dev/null
+++ b/608/CH2/EX2.17/2_17.sce
@@ -0,0 +1,14 @@
+//Problem 2.17: An electric heater consumes 3.6 MJ when connected to a 250 V supply for 40 minutes. Find the power rating of the heater and the current taken from the supply.

+

+//initializing the variables:

+V = 250; // in Volts

+E = 3.6E6; // energy in J

+t = 2400; // in sec

+

+//calculation:

+P = E/t

+I = P/V

+

+printf("\n\nResult\n\n")

+printf("\nPower(P): %.0f Watt(W)",P)

+printf("\nCurrent(I): %.0f Ampere(A)\n",I)
\ No newline at end of file
diff --git a/608/CH2/EX2.18/2_18.sce b/608/CH2/EX2.18/2_18.sce
new file mode 100755
index 000000000..ea0cc9eb6
--- /dev/null
+++ b/608/CH2/EX2.18/2_18.sce
@@ -0,0 +1,16 @@
+//Problem 2.18: Determine the power dissipated by the element of an electric fire of resistance 20ohms when a current of 10 A flows through it. If the fire is on for 6 hours determine the energy used and the cost if 1 unit of electricity costs 7p.

+

+//initializing the variables:

+R = 20; // in ohms

+I = 10; // in ampere

+t = 6; // in hours

+p = 7; // in paise per kWh

+

+//calculation:

+P = I*I*R

+E = P*t/1000 // in kWh

+C = E*p

+

+printf("\n\nResult\n\n")

+printf("\nPower(P): %.0f Watt(W)",P)

+printf("\nCost per week: %.0f Paise(p)\n",C)
\ No newline at end of file
diff --git a/608/CH2/EX2.19/2_19.sce b/608/CH2/EX2.19/2_19.sce
new file mode 100755
index 000000000..19201ad65
--- /dev/null
+++ b/608/CH2/EX2.19/2_19.sce
@@ -0,0 +1,18 @@
+//Problem 2.19: A business uses two 3 kW fires for an average of 20 hours each per week, and six 150 W lights for 30 hours each per week. If the cost of electricity is 7p per unit, determine the weekly cost of electricity to the business.

+

+//initializing the variables:

+P1 = 3; // in kW

+P2 = 150; // in Watt

+n1 = 2; // no. of P1 Equips

+n2 = 6; // no. of P2 Equips

+t1 = 20; // in hours each per week

+t2 = 30; // in hours each per week

+p = 7; // in paise per kWh

+

+//calculation:

+E1 = P1*t1*n1 // in kWh by two P1 eqips

+E2 = P2*t2*n2/1000 // in kWh by six P2 eqips

+Et = E1 + E2

+C = Et * 7

+printf("\n\nResult\n\n")

+printf("\nCost per week: %.0f Paise(p)\n",C)
\ No newline at end of file