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+//Problem 22.11: Determine for the induction motor in problem 22.10 at full load, (a) the rotor current, (b) the rotor copper loss, and (c) the starting current.

+

+//initializing the variables:

+V = 415; // in Volts

+f = 50 ; // in Hz

+nr = 24; // in rev/sec

+p = 4/2; // no. of pole pairs

+R2 = 0.35; // in Ohms

+X2 = 3.5; // in Ohms

+tr = 0.85; // turn ratio N2/N1

+m = 3; // no. of phases

+

+//calculation:

+//ns is the synchronous speed, f is the frequency in hertz of the supply to the stator and p is the number of pairs of poles.

+ns = f/p

+//The slip, s

+s = ((ns - nr)/ns)*100 // in percent

+//Phase voltage, E1 = V/(3^0.5)

+E1 = V/(3^0.5)

+//rotor current,

+Ir = (s/100)*E1*tr/((R2^2 + (X2*(s/100))^2)^0.5)

+//Rotor copper loss 

+Pcl = m*R2*(Ir^2)

+//starting current,

+ss =1

+I2 = ss*tr*E1/((R2^2 + (X2*ss)^2)^0.5)

+

+printf("\n\n Result \n\n")

+printf("\n(a)rotor current is %.2f A",Ir)

+printf("\n(b)Total copper loss is %.2f W",Pcl)

+printf("\n(c)starting current is %.2f A",I2)
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