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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Problem 21.21: A 200 V, d.c. shunt-wound motor has an armature resistance of 0.4 ohm and at a certain load has an armature current of 30 A and runs at 1350 rev/min. If the load on the shaft of the motor is increased so that the armature current increases to 45 A, determine the speed of the motor, assuming the flux remains constant.
+
+//initializing the variables:
+Ia1 = 30; // in Amperes
+Ia2 = 45; // in Amperes
+Ra = 0.4; // in ohm
+n1 = 1350/60; // in Rev/sec
+V = 200; // in Volts
+
+//calculation:
+//The relationship E proportional to (Phi*n) applies to both generators and motors. For a motor,
+//E = V - (Ia*Ra)
+E1 = V - (Ia1*Ra)
+E2 = V - (Ia2*Ra)
+//The relationship, E1/E2 = Phi1*n1/Phi2*n2, applies to both generators and motors. Since the flux is constant, Phi1 = Phi2
+Phi2 = Phi1
+n2 = E2*Phi1*n1/(Phi2*E1)
+
+printf("\n\n Result \n\n")
+printf("\n the speed of the motor is %.2f rev/sec ",n2) \ No newline at end of file