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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+//Problem 21.18: The shaft torque of a diesel motor driving a 100 V d.c. shunt-wound generator is 25 Nm. The armature current of the generator is 16 A at this value of torque. If the shunt field regulator is adjusted so that the flux is reduced by 15%, the torque increases to 35 Nm. Determine the armature current at this new value of torque.
+
+//initializing the variables:
+T1 = 25; // in Nm
+T2 = 35; // in Nm
+Ia1 = 16; // in Amperes
+V = 100; // in Volts
+x = 0.15;
+
+//calculation:
+//the shaft torque T of a generator is proportional to (phi*Ia), where Phi is the flux and Ia is the armature current. Thus, T = k*Phi*Ia, where k is a constant.
+//The torque at flux phi1 and armature current Ia1 is T1 = k*Phi1*Ia1.
+//similarly T2 = k*Phi2*Ia2
+Phi2 = (1 - x)*Phi1
+Ia2 = T2*Ia1*Phi1/(Phi2*T1)
+
+printf("\n\n Result \n\n")
+printf("\n armature current at the new value of torque is %.2f A ",Ia2) \ No newline at end of file