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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH20/EX20.24/20_24.sce | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '608/CH20/EX20.24/20_24.sce')
| -rwxr-xr-x | 608/CH20/EX20.24/20_24.sce | 24 |
1 files changed, 24 insertions, 0 deletions
diff --git a/608/CH20/EX20.24/20_24.sce b/608/CH20/EX20.24/20_24.sce new file mode 100755 index 000000000..bdd04556e --- /dev/null +++ b/608/CH20/EX20.24/20_24.sce @@ -0,0 +1,24 @@ +//Problem 20.24: An a.c. source of 24 V and internal resistance 15 kohm is matched to a load by a 25:1 ideal transformer. Determine (a) the value of the load resistance and (b) the power dissipated in the load.
+
+//initializing the variables:
+tr = 25; // teurn ratio
+V = 24; // in Volts
+R1 = 15000; // in Ohms
+Rin = 15000; // in ohms
+
+//calculation:
+//Turns ratio, tr = N1/N2 = V1/V2
+//For maximum power transfer R1 needs to be equal to 15 kohm
+RL = R1/(tr^2)
+//The total input resistance when the source is connected to the matching transformer is
+Rt = Rin + R1
+//Primary current,
+I1 = V/Rt
+//N1/N2 = I2/I1
+I2 = I1*tr
+//Power dissipated in load resistor RL
+P = I2*I2*RL
+
+printf("\n\n Result \n\n")
+printf("\n (a) the load resistance is %.0f ohm", RL)
+printf("\n (b) power dissipated in the load resistor is %.2E W", P)
\ No newline at end of file |