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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH20/EX20.21/20_21.sce | |
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initial commit / add all books
Diffstat (limited to '608/CH20/EX20.21/20_21.sce')
-rwxr-xr-x | 608/CH20/EX20.21/20_21.sce | 14 |
1 files changed, 14 insertions, 0 deletions
diff --git a/608/CH20/EX20.21/20_21.sce b/608/CH20/EX20.21/20_21.sce new file mode 100755 index 000000000..67d67f53c --- /dev/null +++ b/608/CH20/EX20.21/20_21.sce @@ -0,0 +1,14 @@ +//Problem 20.21: The output stage of an amplifier has an output resistance of 112 ohm. Calculate the optimum turns ratio of a transformer which would match a load resistance of 7 ohm to the output resistance of the amplifier.
+
+//initializing the variables:
+R1 = 112; // in Ohms
+RL = 7; // in Ohms
+
+//calculation:
+//The equivalent input resistance, R1 of the transformer needs to be 112 ohm for maximum power transfer.
+//R1 = RL*(tr^2)
+// tr = N1/N2 turn ratio
+tr = (R1/RL)^0.5
+
+printf("\n\n Result \n\n")
+printf("\n the optimum turns ratio is %.0f ", tr)
\ No newline at end of file |