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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH15/EX15.23 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '608/CH15/EX15.23')
| -rwxr-xr-x | 608/CH15/EX15.23/15_23.sce | 13 |
1 files changed, 13 insertions, 0 deletions
diff --git a/608/CH15/EX15.23/15_23.sce b/608/CH15/EX15.23/15_23.sce new file mode 100755 index 000000000..0ba84a0c2 --- /dev/null +++ b/608/CH15/EX15.23/15_23.sce @@ -0,0 +1,13 @@ +//Problem 15.23: A filter in the form of a series L–R–C circuit is designed to operate at a resonant frequency of 5 kHz. Included within the filter is a 20 mH inductance and 10 ohm resistance. Determine the bandwidth of the filter.
+
+//initializing the variables:
+L = 20E-3; // in Henry
+R = 10; // in ohms
+fr = 5000; // in Hz
+
+//calculation:
+Qr = (2*%pi*fr)*L/R
+bw = fr/Qr
+
+printf("\n\n Result \n\n")
+printf("\n Bandwidth, (f2-f1) = %.1f Hz",bw)
\ No newline at end of file |