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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH15/EX15.12 | |
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initial commit / add all books
Diffstat (limited to '608/CH15/EX15.12')
-rwxr-xr-x | 608/CH15/EX15.12/15_12.sce | 29 |
1 files changed, 29 insertions, 0 deletions
diff --git a/608/CH15/EX15.12/15_12.sce b/608/CH15/EX15.12/15_12.sce new file mode 100755 index 000000000..da3e084fb --- /dev/null +++ b/608/CH15/EX15.12/15_12.sce @@ -0,0 +1,29 @@ +//Problem 15.12: A coil of inductance 159.2 mH and resistance 20 ohms is connected in series with a 60 ohms resistor to a 240 V, 50 Hz supply. Determine (a) the impedance of the circuit, (b) the current in the circuit, (c) the circuit phase angle, (d) the p.d. across the 60 ohms resistor and (e) the p.d. across the coil. (f) Draw the circuit phasor diagram showing all voltages.
+
+//initializing the variables:
+R = 60; // in ohms
+Rc = 20; // in ohms
+L = 159.2E-3; // in henry
+f = 50; // in Hz
+V = 240; // in volts
+
+//calculation:
+XL = 2*%pi*f*L
+Rt = R + Rc
+Z = (Rt^2 + XL^2)^0.5
+I = V/Z
+phid = atan(XL/Rt)*180/%pi
+VR = I*R
+Zc = (Rc^2 + XL^2)^0.5
+Vc = I*Zc
+VL = I*XL
+VRc = I*Rc
+
+printf("\n\n Result \n\n")
+printf("\n (a)Impedance, Z = %.2f ohms",Z)
+printf("\n (b)current, I = %.3f A",I)
+printf("\n (c)circuit phase angle is %.0f°",phid)
+printf("\n (d)p.d. across resistance, VR = %.1f V", VR)
+printf("\n (e)p.d. across coil, Vc = %.0f V",Vc)
+printf("\n (f1)p.d. across Inductor, VL = %.1f V",VL)
+printf("\n (f2)p.d. across coil resistance, VRc = %.2f V",VRc)
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