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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /608/CH13/EX13.21 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '608/CH13/EX13.21')
| -rwxr-xr-x | 608/CH13/EX13.21/13_21.sce | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/608/CH13/EX13.21/13_21.sce b/608/CH13/EX13.21/13_21.sce new file mode 100755 index 000000000..f6d2cc149 --- /dev/null +++ b/608/CH13/EX13.21/13_21.sce @@ -0,0 +1,17 @@ +//Problem 13.21: A d.c. source has an open-circuit voltage of 30 V and an internal resistance of 1.5 ohm. State the value of load resistance that gives maximum power dissipation and determine the value of this power.
+
+//initializing the variables:
+V = 30; // in volts
+r = 1.5; // in ohms
+
+//calculation:
+//current I = E/(r + RL)
+//For maximum power, RL = r
+RL = r
+I = V/(r + RL)
+//Power, P, dissipated in load RL, P
+P = RL*I^2
+
+printf("\n\n Result \n\n")
+printf("\n (a) the value of the load resistor RL is %.1f ohm",RL)
+printf("\n (b) maximum power dissipation = %.0f W",P)
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