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+//Problem 13.09: Use Th´evenin’s theorem to determine the current I flowing in the 4 ohm resistor shown in Figure 13.30(a). Find also the power dissipated in the 4 ohm resistor.

+

+//initializing the variables:

+E1 = 4; // in volts

+E2 = 2; // in volts

+R1 = 2; // in ohms

+R2 = 1; // in ohms

+R3 = 4; // in ohms

+

+//calculation:

+//The 4 ohm resistance branch is short-circuited as shown in Figure 13.30(b).

+//Current I1

+I1 = (E1 - E2)/(R1 + R2)

+//p.d. across AB, E

+E = E1 - I1*R1

+//the resistance ‘looking-in’ at a break made between A and B is given by

+r = R2*R1/(R2 + R1)

+//The equivalent Th´evenin’s circuit is shown in Figure 13.30(d), the current in the 4ohm resistance is given by:

+I = E/(r + R3)

+//Power dissipated in R3

+P3 = R3*I^2

+

+printf("\n\n Result \n\n") 

+printf("\n the current in the 4 ohm resistance is given by %.3f A",I)

+printf("\n power disipated in 4 ohm resistor is given by %.3f W",P3)
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