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+//Problem 13.08: For the network shown in Figure 13.29(a) determine the current in the 0.8 ohm resistor using Th´evenin’s theorem.

+

+//initializing the variables:

+V = 12; // in volts

+R1 = 5; // in ohms

+R2 = 1; // in ohms

+R3 = 4; // in ohms

+R = 0.8; // in ohms

+

+//calculation:

+//The 0.8 ohm resistance branch is short-circuited as shown in Figure 13.29(b).

+//Current I1

+I1 = V/(R1 + R2 + R3)

+//p.d. across AB, E

+E = R3*I1

+//the resistance ‘looking-in’ at a break made between A and B is given by

+r = R3*(R1 + R2)/(R2 + R1 + R3)

+//The equivalent Th´evenin’s circuit is shown in Figure 13.29(d), the current in the 0.8 ohm resistance is given by:

+I = E/(r + R)

+

+printf("\n\n Result \n\n") 

+printf("\n the current in the 0.8 ohm resistance is given by %.1f A",I)
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