initial commit / add all books

1 files changed, 40 insertions, 0 deletions

diff --git a/608/CH13/EX13.06/13_06.sce b/608/CH13/EX13.06/13_06.sce
new file mode 100755
index 000000000..008a7d777
--- /dev/null
+++ b/608/CH13/EX13.06/13_06.sce
@@ -0,0 +1,40 @@
+//Problem 13.06: For the circuit shown in Figure 13.16, find, using the superposition theorem, (a) the current flowing in and the pd across the 18 ohm resistor, (b) the current in the 8 V battery and (c) the current in the 3 V battery.

+

+//initializing the variables:

+E1 = 8; // in volts

+E2 = 3; // in volts

+R1 = 3; // in ohms

+R2 = 2; // in ohms

+R3 = 18; // in ohms

+

+//calculation:

+//Removing source E2 gives the circuit of Figure 13.17(a).

+//The current directions are labelled as shown in Figure 13.17(a), I1 flowing from the positive terminal of E1.

+//From Figure 13.17(b), I1

+r1 = 1/(1/R2 + 1/R3)

+I1 = E1/(R1 + r1)

+//From Figure 13.17(a), I2

+I2 = (R3/(R3 + R2))*I1

+I3 = (R2/(R3 + R2))*I1

+//Removing source E1 gives the circuit of Figure 13.18(a)

+//The current directions are labelled as shown in Figures 13.18(a) and 13.18(b), I4 flowing from the positive terminal of E2

+//From Figure 13.18(c), I4

+r2 = 1/(1/R3 + 1/R1)

+I4 = E2/(r2 + R2)

+//From Figure 13.18(b), I5

+I5 = (R3/(R1 + R3))*I4

+I6 = (R1/(R1 + R3))*I4

+//Resultant current in the R3 resistor

+I18 = I3 - I6

+//P.d. across the R3

+V3 = I18*R3

+//Resultant current in the E1

+Ie1 = I1 + I5

+//Resultant current in the E2

+Ie2 = I2 + I4

+

+printf("\n\n Result \n\n") 

+printf("\n Resultant current in the 18 ohm resistor is %.3f A",I18)

+printf("\n P.d. across the 18 ohm resistor is %.3f V",V3)

+printf("\n Resultant current in the E1 is %.3f A",Ie1)

+printf("\n Resultant current in the E2 is %.3f A",Ie2)
\ No newline at end of file