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authorpriyanka2015-06-24 15:03:17 +0530
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+
+clear;
+clc;
+printf("\t Example 7.2\n");
+
+//part(i)
+a1=229.7; //solubility at 60 degree
+a2=174.7; //solubility at 60 degree
+t1=68; // percentage of sodium nitrate
+t2=30.34;
+x1=a1/329.7 *100; //percentage of saturated solution at 50 degree
+tw=(t1/32)/(x1/t2); //the percentage saturation
+printf("\nthe percentage saturation is :%f percent",tw*100);
+
+//part(ii)
+//let x be the weight of Cesium chloride crystal formed after crystallisation
+x=poly([0],'x'); //calc. x the weight of crystal
+t=roots(1000*.68-(x+(1000-x)*174.7/274.7));
+printf("\n the weight of CaCl2 crystal formed after crystallisation :%f kg",t);
+
+//part(iii)
+yield=t/680; //yield = weight of CaCl2 crystal formed/weight of CaCl2
+printf("\n the percentage yield of Cesium chloride is:%f percent",yield*100);
+//end \ No newline at end of file