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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /599/CH7/EX7.7/example7_7.sce | |
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initial commit / add all books
Diffstat (limited to '599/CH7/EX7.7/example7_7.sce')
| -rwxr-xr-x | 599/CH7/EX7.7/example7_7.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/599/CH7/EX7.7/example7_7.sce b/599/CH7/EX7.7/example7_7.sce new file mode 100755 index 000000000..9cd10f997 --- /dev/null +++ b/599/CH7/EX7.7/example7_7.sce @@ -0,0 +1,18 @@ +
+clear;
+clc;
+printf("\t Example 7.7\n");
+
+s1=139.8; //solubility at 80 degree per 100 gm of water
+s2=110.5; //solubility at 20 degree per 100 gm of water
+w2=174.2; //molecular weight of K2CO3.10H2O
+M1=(138/w2)*100; //water present in 100kg of K2CO3.10H2O
+//let x be the quantity of Na2CO3.10H2O
+x=poly([0],'x'); //calc. x the weight of crystal
+t=roots(500*(139.8/239.8)-.7921*x-(500-x)*110.5/210.5);
+printf("\n the weight of quantity of K2CO3.10H2O formed :%f kg",t);
+
+p=(174/138)*500*(139.8/239.8); //weight of crystal present in the original solution
+yield=t/p; //percentage yield
+printf("\n percentage yield :%f percent",yield*100);
+//end
\ No newline at end of file |