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authorpriyanka2015-06-24 15:03:17 +0530
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+clear;
+//clc();
+
+// Example 6.2
+// Page: 109
+printf("Example-6.2 Page no.-109\n\n");
+
+//***Data***//
+n_eth = 1;//[mol]
+W_water = 1;//[kg]
+Temp = 20;//[C]
+// For pure ethanol at 20C
+v_ethanol = 58.4;//[cm^(3)/mol]
+v_ethanol = v_ethanol/1000;//[L/mol]
+v_water = 1.0019;//[L/1000g]
+// Molality of ethanol in water is
+m = n_eth/W_water;//[molal]
+// We have the equation used in the previous example as
+V_final_mix = 1.0019+0.054668*m-0.000418*m^(2);
+// Where 'V' is( solution volume, liters per 1000g of water ) and 'm' is the molality of ethanol in water
+// V is the final volume of the solution
+// The volume expansion on moxing is
+V_exp = V_final_mix-v_ethanol-v_water;//[L]
+V_exp = V_exp*1000;//[cm^(3)]
+printf("Volume change on mixing etanol and water is %0.3f cubic cm",V_exp);
+// We see that there is a net contraction on mixing of the volume of the ethanol added.
+