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author | priyanka | 2015-06-24 15:03:17 +0530 |
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committer | priyanka | 2015-06-24 15:03:17 +0530 |
commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
tree | ab291cffc65280e58ac82470ba63fbcca7805165 /587/CH6 | |
download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip |
initial commit / add all books
Diffstat (limited to '587/CH6')
-rwxr-xr-x | 587/CH6/EX6.1/example6_1.sce | 25 | ||||
-rwxr-xr-x | 587/CH6/EX6.2/example6_2.sce | 19 |
2 files changed, 44 insertions, 0 deletions
diff --git a/587/CH6/EX6.1/example6_1.sce b/587/CH6/EX6.1/example6_1.sce new file mode 100755 index 000000000..04ba74322 --- /dev/null +++ b/587/CH6/EX6.1/example6_1.sce @@ -0,0 +1,25 @@ +clear;
+clc;
+
+//Example6.1[Temperature Rise of Oil is a Journal Bearing]
+//Given:-
+k=0.145;//[W/m.K]
+mu=0.8374;//[kg/m.s]or[N.s/m^2]
+T1=20;//Temperature of both the plates[degree Celcius]
+t=0.002;//Thickness of oil film between the plates[m]
+v=12;//Velocity with which plates move[m/s]
+//Solution (a):-
+//Relation between velocity and temperature variation
+disp("T(y)=T0+(mu*(v^2)/(2*k))[(y/L)-((y/L)^2)]")
+//Solution(b):-
+//The location of maximum temperature is determined by setting dT/dy=0 and solving for y
+//(mu*(v^2)/(2*k*L))*(1-(2*y/L))=0
+L=1;//Random initialisation of variable L, where L is length of plates
+y=L/2;
+//T_max=T(L/2)
+T_max=T1+((mu*(v^2)/(2*k))*(((L/2)/L)-(((L/2)^2)/(L^2))));
+disp("degree Celcius",ceil(T_max),"Maximum temperature occurs at mid plane and its value is")
+//heat flux q0=-kdt/dy|y=0;=-kmu*v^2/(2*k*L)
+q0=-(mu*k*(v^2)/(2*k*t))/1000;//Heat flux from one plate [kW/m^2]
+qL=-((k*mu*(v^2))*(1-2)/(2*k*t*1000));//Heat flux from another plate[kW/m^2]
+disp("kW/m^2",qL,"Heat fluxes at the two plates are equal in magnitude but opposite in sign and the value of magnitude is")
diff --git a/587/CH6/EX6.2/example6_2.sce b/587/CH6/EX6.2/example6_2.sce new file mode 100755 index 000000000..a705ad377 --- /dev/null +++ b/587/CH6/EX6.2/example6_2.sce @@ -0,0 +1,19 @@ +clear;
+clc;
+
+//Example6.2[Finding Convection Coefficient from Drag Measurement]
+//Given:-
+//Properties of air
+rho=1.204;//[kg/m^3]
+Cp=1007;//[J/kg.K]
+Pr=0.7309;//Prandtl number
+w=2;//Width of plate[m]
+L=3;//Characteristic length of plate[m]
+v=7;//velocity of air[m/s]
+Fd=0.86;//Total grag force[N]
+//Solution:-
+As=2*w*L;//Since both sides of plate are exposed to air flow[m^2]
+//For flat plates drag force is equivalent to friction coefficient Cf
+Cf=Fd/(rho*As*(v^2)/2);
+h=(Cf*rho*v*Cp)/(2*(Pr^(2/3)));//[W/m^2.degree Celcius]
+disp("respectively","W/m^2.degree Celcius",h,"and",Cf,"Friction Factor and average heat transfer coefficient are")
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