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+clear;

+clc;

+

+//Example2.11[Heat Conduction in a Plane Wall]

+//Given:-

+k_wall=1.2;//Thermal conductivity of wall[W/m.degree Celcius]

+L=0.2;//Thickness of wall[m]

+As=15;//Surface area[m^2]

+T1=120,T2=50;//The two sides of the wall are maintained at these constant temperatures[degree Celcius]

+//Solution (a)

+disp("Differential equation can be expressed as d^2(T)/(dx^2)=0")

+disp("with boundary conditions ")

+disp("degree Celcius",T1,"T(0)=T1=")

+disp("degree Celcius",T2,"T(L)=T2=")

+disp("integrating this we get,")

+disp("dT/dx=C1", ,"where C1 is an arbitrary constant")

+disp("integrating we obtain temperature to follow following relation :-")

+disp("and substituting values in above equation","T(x)=((T2-T1)/L)*x+T1 ")

+T3=(((T2-T1)/L)*(0.1))+T1;

+disp("degree Celcius",T3,"The value of temperature at x=0.1m is")

+Q_wall=-k_wall*As*((T2-T1)/L);//[W]

+disp("W",Q_wall,"The rate of heat conduction through the wall is")
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