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+clear;

+clc;

+

+//Example14.10[Mass Convection inside a Circular Pipe]

+//Given:-

+D=0.015;//Inner Diameter[m]

+T=300;//Temp of air[K]

+P=1;//Pressure of air[atm]

+v=1.2;//Average velocity of air[m/s]

+nu=1.58*10^(-5);//Viscosity[m^2/s]

+//Solution:-

+//Water is Species Aand air is species B

+D_AB=(1.87*10^(-10))*(T^2.072)/P;//[m^2/s]

+disp("m^2/s",D_AB,"The mass diffusivity of water vapor in air at 300K is")

+Re=v*D/nu;

+disp(round(Re),"The Reynolds number for internal flow is")

+if(Re<2300) then

+    disp("laminar Flow")

+    Sh=3.66;//Sherwood number equals to Nusselt number

+    h_mass=Sh*D_AB/D;//[m/s]

+    disp("m/s",h_mass,"The mass transfer coefficient is")

+else

+    disp("Flow is not laminar")

+end