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+

+clear;

+clc;

+

+printf("\t Example 8.3\n");

+

+T1=323;     //wall temp.,K

+T2=293;     //air temp.,K

+H=0.3;      //height of wall, m

+v1=16.45*10^-6;   // molecular diffusivity, m^2/s

+b=1/T2;    // b=1/v*d(R*T/p)/dt=1/To   characterisation constant of thermal expansion of solid, K^-1

+v2=2.318*10^-5;    //molecular diffusivity, m^2/s

+Pr=0.71;   //prandtl no.

+

+ Ral=9.8*b*(T1-T2)*H^3/((1.566*10^-5)*(2.203*10^-5));    // Rayleigh no.

+ Nu=0.678*Ral^(0.25)*(Pr/(0.952+Pr))^(1/4);        // nusselt no.

+ h=Nu*0.0267/H     // average heat transfer coefficient, W/m^2/K

+ 

+ Nu1=0.68+0.67*((Ral)^(1/4)/(1+(0.492/Pr)^(9/16))^(4/9));    //churchill correlation 

+ 

+ h1=Nu1*(0.0267/0.3)-.11;     //average heat transfer coefficient, W/m^2/K

+ 

+ 

+printf("\t correlation average heat transfer coefficient is :%.2f W/m^2/K\n",h1)

+printf("\t the prediction is therefore within 5 percent of corelation .we should use the latter result in preference to the theoritical one, although the difference is slight.")

+  //end
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