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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /581/CH6/EX6.3 | |
| download | Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.gz Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.tar.bz2 Scilab-TBC-Uploads-b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b.zip | |
initial commit / add all books
Diffstat (limited to '581/CH6/EX6.3')
| -rwxr-xr-x | 581/CH6/EX6.3/Example6_3.sce | 20 |
1 files changed, 20 insertions, 0 deletions
diff --git a/581/CH6/EX6.3/Example6_3.sce b/581/CH6/EX6.3/Example6_3.sce new file mode 100755 index 000000000..261b3e723 --- /dev/null +++ b/581/CH6/EX6.3/Example6_3.sce @@ -0,0 +1,20 @@ +
+clear;
+clc;
+
+printf("\t Example 6.3\n");
+
+l=0.5; //total length of surface,m
+Cf=0.00607; //overall friction coefficient
+tw=1.183*(2.25)*Cf/2; // wall shear, kg/(m*s^2)
+
+a=0.5; //ratio of wall shear at x=l and average wall shear
+
+//tw(x)=twavg where 0.664/(x^0.5)=1.328/(47,)893, x=1/8 m thus the wall shear stress plummets to twavg one fourth of the way from the leading edge and drops only to one half of twavg in the remaining 75 percent plate.x<600*1.566*10^(-5)/1.5=0.0063 m.
+
+// preceding analysis should be good over almost 99 percent of the 0.5 m length of the surface.
+
+printf("\t overall friction coefficient is : %f\n",Cf);
+printf("\t wall shear is :%f kg/(m*s^2)\n",tw);
+printf("\t the preceding analysis should be good over almost 99 percent of the 0.5m length of the surface.")
+//end
\ No newline at end of file |