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+//Steam enters a turbine with a pressure of 30 bar, a temperature of 400C, a velocity of 160 m/s. Steam exits as saturated vapor at 100C with a velocity of 100 m/s. At steady state, the turbine develops work at a rate of 540 kJ per kg of steam flowing through the turbine. Heat transfer between the turbine and its surroundings occurs at an average outer surface temperature of 350 K. Develop a full accounting of the net exergy carried in by the steam, per unit mass of steam flowing. Neglect the change in potential energy between inlet and exit. Let T0 = 25C, p0=  1 atm.

+

+//solution

+

+//variable initialization

+p1 = 30                                                 //pressure of entering steam in bar

+t1 = 400                                                //temperature of entering steam in degree celcius

+v1 = 160                                                //velocity of entering steam in m/s

+t2 = 100                                                //temperature of exiting saturated vapor in degree celcius

+v2 = 100                                                //velocity of exiting saturated vapor in m/s

+W = 540                                                 //rate of work developed in kj per kg of steam

+Tb = 350                                                //the temperature on the boundary where heat transfer occurs in kelvin

+T0 = 25                                                 //in degree celcius

+p0 = 1                                                  //in atm

+

+//from table A-4

+h1 = 3230.9                                             //in kj/kg

+s1 = 6.9212                                             //in kj/kg.k

+//from table A-2 

+h2 = 2676.1                                             //in kj/kg

+s2 = 7.3549                                             //in kj/kg.k

+

+DELTAef = (h1-h2)-(T0+273)*(s1-s2)+(v1^2-v2^2)/(2*1000)              //The net exergy carried in per unit mass of steam flowing in kj/kg

+

+//from example 6.6

+Q = -22.6                                               //in kj/kg

+Eq = (1-(T0+273)/Tb)*(Q)                                      //exergy transfer accompanying heat in kj/kg

+

+Ed = (1-(T0+273)/Tb)*(Q)-W+(DELTAef)                          //The exergy destruction determined by rearranging the steady-state form of the exergy rate balanceff

+

+printf('balance sheet')

+printf('\nNet rate of exergy in:\t%f',DELTAef)

+printf('\nDisposition of the exergy:')

+printf('\n• Rate of exergy out')

+printf('\nwork\t%f',W)

+printf('\nheat transfer\t%f',-Eq)

+printf('\n• Rate of exergy destruction\t%f',Ed)

+

+

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