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authorprashantsinalkar2017-10-10 12:27:19 +0530
committerprashantsinalkar2017-10-10 12:27:19 +0530
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+// Implementation of example 5.6
+// Basic and Applied Thermodynamics by P.K.Nag
+
+clc
+clear
+
+Va=270 // (air speed in m/s)
+Ha=260 // (enthalpy of air in kJ/kg)
+Hg=912 // (enthalpy of gas in kJ/kg)
+Ef=44500 // (energy in kJ/kg)
+wf=0.019 // (fuel ratio)
+Q=21 // (heat loss in kJ/kg)
+wg=wf+1;
+// it is given that 5% of energy is not released in reaction
+Eg=0.05*Ef*(wf/wg);
+// the steady flow rate equation is wa*(hg+Va^2/2)+wf*Ef+Q=wg*(hg+Vg^2/2+Eg)
+temp=((Ha+Va*Va/2000)+wf*Ef-Q-wg*(Hg+Eg));
+temp=temp*wg*2000;
+Vg=sqrt(temp);
+printf("velocity of exhaust gas = %.2f",Vg);
+// end \ No newline at end of file