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author | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
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committer | prashantsinalkar | 2017-10-10 12:27:19 +0530 |
commit | 7f60ea012dd2524dae921a2a35adbf7ef21f2bb6 (patch) | |
tree | dbb9e3ddb5fc829e7c5c7e6be99b2c4ba356132c /555/CH4/EX4.1/1.sce | |
parent | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (diff) | |
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-rw-r--r-- | 555/CH4/EX4.1/1.sce | 18 |
1 files changed, 18 insertions, 0 deletions
diff --git a/555/CH4/EX4.1/1.sce b/555/CH4/EX4.1/1.sce new file mode 100644 index 000000000..4f50b097c --- /dev/null +++ b/555/CH4/EX4.1/1.sce @@ -0,0 +1,18 @@ +// Implementation of example 4.1
+// Basic and Applied Thermodynamics by P.K.Nag
+// page 72
+
+clc
+clear
+
+// First law of Thermodynamics for stationary system is dQ = dU+W
+dQ=-37.6 // (heat transfer in kJ)
+v1=0.3 // (initial volume in m^3)
+p=0.105 // (pressure in MPa)
+v2=0.15 // (final volume in m^3)
+
+W=p*(v2-v1)*1000;
+// now according to first law
+dU=W-dQ;
+printf("Change in internal energy of gas is = %.2f kJ",dU);
+// end
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