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| author | priyanka | 2015-06-24 15:03:17 +0530 |
|---|---|---|
| committer | priyanka | 2015-06-24 15:03:17 +0530 |
| commit | b1f5c3f8d6671b4331cef1dcebdf63b7a43a3a2b (patch) | |
| tree | ab291cffc65280e58ac82470ba63fbcca7805165 /542/CH11/EX11.7/Example_11_7.sce | |
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Diffstat (limited to '542/CH11/EX11.7/Example_11_7.sce')
| -rwxr-xr-x | 542/CH11/EX11.7/Example_11_7.sce | 64 |
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diff --git a/542/CH11/EX11.7/Example_11_7.sce b/542/CH11/EX11.7/Example_11_7.sce new file mode 100755 index 000000000..818883bb9 --- /dev/null +++ b/542/CH11/EX11.7/Example_11_7.sce @@ -0,0 +1,64 @@ +clear;
+clc;
+printf('Example 11.7'); //Example 11.7
+// Find Number of theoretical plates needed and the position of entry for the feed
+
+F = 100; //Feed [kmol]
+
+function[f]=Feed(x)
+ f(1)=x(1)+x(2)-100; //Overall mass Balance
+ f(2)=0.9*x(1)+.1*x(2)-(100*.4); //A balance on MVC,benzene
+ funcprot(0)
+endfunction
+x = [50 50];
+product = fsolve(x,Feed);
+
+//Using notation of figure 11.13
+Ln = 3*product(1);
+Vn = Ln + product(1);
+
+//Reflux to the plate
+Lm = Ln + F;
+Vm = Lm - product(2);
+
+//Equilibrium Composition
+xt = .79; yt = .9;
+//From Top eqm line
+yt1 = (Ln/Vn)*xt + (product(1)/Vn);
+xt1=.644; //Thus from Eqm curve for yt1
+//From Top eqm line
+yt2 = (Ln/Vn)*xt1 + (product(1)/Vn);
+xt2=.492; //Thus from Eqm curve for yt2
+//From Top eqm line
+yt3 = (Ln/Vn)*xt2 + (product(1)/Vn);
+xt3=.382; //Thus from Eqm curve for yt3
+//From II Eqm Line
+yt4 = (Lm/Vm)*xt3 - (product(2)/Vm)*.1;
+xt4=.2982; //Thus from Eqm curve for yt4
+//From II Eqm Line
+yt5 = (Lm/Vm)*xt4 - (product(2)/Vm)*.1;
+xt5=.208; //Thus from Eqm curve for yt5
+//From II Eqm Line
+yt6 = (Lm/Vm)*xt5 - (product(2)/Vm)*.1;
+xt6=.120; //Thus from Eqm curve for yt6
+//From II Eqm Line
+yt7 = (Lm/Vm)*xt6 - (product(2)/Vm)*.1;
+xt7=.048; //Thus from Eqm curve for yt7
+
+//Equilibrium Data
+y=[0 yt7 yt6 yt5 yt4 yt3 yt2 yt1 yt];
+x=[0 xt7 xt6 xt5 xt4 xt3 xt2 xt1 xt];
+//Top Equilibrium Line equation 11.35
+x1 = linspace(0,.79,100);
+y1 = (Ln/Vn)*x1 + (product(1)/Vn);
+//Equilibrium Line equation 11.37
+x2 = linspace(0.048,.44,100);
+y2 = (Lm/Vm)*x2 - (product(2)/Vm)*.1;
+clf();
+plot(x,y,x1,y1,x2,y2);
+xtitle("Lewis-Sorel Method", "Mole fraction of C6H6 in Liquid (x)", "Mole Fraction C6H6 in Vapor (y)");
+legend ("Equilirium Plot", "Top Eqm Line", "Bottom Eqm Line");
+printf("\n\n As the least point on equilibrium Line xt-7 correspond to reboiler, and there will be seven plates");
+
+
+//END
\ No newline at end of file |