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authorpriyanka2015-06-24 15:03:17 +0530
committerpriyanka2015-06-24 15:03:17 +0530
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+disp("given:")
+disp("The voltage generated by an transducer which is connected to differential amplifier is Vdm=50mV ")
+Vdm=50*(1/1000)//Vdm in volts
+disp("Vcm=5V")
+Vcm=5
+disp("Vout should be equal to 10V")
+Vout=10
+disp("The unwanted output component owing to the common-mode input is to be less than 1% of the wanted component i.e Voutcm=1% of Voutdm")
+Voutcm=(1/100)*10
+printf(" Voutcm=%f",Voutcm)
+disp("Let amplifier differential-mode gain be Adm")
+disp("Vout,Admand Vdm are related as")
+disp("Vout=Adm*Vdm------(1)")
+disp("Adm=Vout/Vdm")
+Adm=Vout/Vdm
+printf(" Therefore amplifier differential-mode gain(Adm)=%d",Adm)
+disp("Equation (1)can also be used for calculating unwanted output component")
+disp("Unwanted components arise when operating in common-mode")
+disp("Acm=Voutcm/Vcm")
+Acm=Voutcm/Vcm
+printf(" Common-mode gain Acm=%f",Acm)
+disp("Now CMRR can be calculated using relation")
+disp("CMRR=Adm/Acm")
+CMRR=Adm/Acm
+printf(" There fore CMRR of amplifier should be greater than or equal to %f",CMRR)
+printf(" CMRR>=%d",CMRR)