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+//Engineering and Chemical Thermodynamics
+//Example 3.5
+//Page no:124
+
+clear ; clc ;
+//Given
+P_1 = 300 * 10^3 ; //[N/m^2]
+T_1 = 700 ; // [*C]
+V_bar_1 = 20 ; //[m/s]
+P_2 = 200 * 10^3 ; // [N/m^2]
+h_cap_1 = 3927.1 * 10^3 ; // [J/kg] , From table
+S_cap_1 = 8.8319 ; // [kJ/kgK] , From table
+
+S_cap_2 = S_cap_1 ; // Reverssible adiabatic process
+T2 = 623 ; // [*C] ,From table by interpolation
+h_cap_2 = 3754.7 * 10^3 ; // [J/kgK] ,From table by interpolation
+V_bar_2 = sqrt(2 * (h_cap_1 - h_cap_2) + V_bar_1^2) ;
+disp(" Example: 3.5 Page no : 124") ;
+printf('\n The final temperature is %g C and the exit velocity is %g m/s',T2,V_bar_2);